
implementa
IAlgebra
免費
9for iPhone, iPad and more
Age Rating
implementa 螢幕截圖
About implementa
The App provides users with a learning platform to explore and solve algebra f(x) exercises. In each step of problem solving, by selecting the mathematical operation provided by the App, users can complete the problem-solving in exploration and learning like a driver controlling the steering wheel, master the concept of algebra in the integration of knowledge and action, and gain the ability to use concepts and knowledge to solve problems. If you want the answer, you can use a group of Ai. If you want the ability, you can try IA to make carbon-based life smarter! Not GPUs.
App 提供用户一个探索求解代数f(x)习题的学习平台。在解题的每一步,通过选择App提供的数学操作,用户如车手操控方向盘般,在探索学习中完成解题, 在知行合一中掌握代数的概念,获得运用概念与知识解决问题的能力。你想要答案,可以用一众Ai,你想要能力,可以试试IA,让碳基生命更智能!而不是GPU们。
App 提供用户一个探索求解代数f(x)习题的学习平台。在解题的每一步,通过选择App提供的数学操作,用户如车手操控方向盘般,在探索学习中完成解题, 在知行合一中掌握代数的概念,获得运用概念与知识解决问题的能力。你想要答案,可以用一众Ai,你想要能力,可以试试IA,让碳基生命更智能!而不是GPU们。
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最新版本9更新日誌
Last updated on 2025年08月28日
歷史版本
1.Support dark mode.
2.The menu only provides operations that can be performed and need to be performed to reduce information overload.
3.For operations that require inputting algebraic formulas, after completing the input, you need to click on the selected algebraic formula, equal sign, and inequality sign to perform the operation. All other operations can be executed after selecting the correct answer.
1.支持深色模式。
2.菜单中仅提供能被执行与需要执行的操作,减少信息过载。
3.对于需要输入代数式的操作,完成输入后需要再点击选择的代数式、等号、不等号,以便执行操作,
其它所有操作选中正确答案后即可执行操作。
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Version History
9
2025年08月28日
1.Support dark mode.
2.The menu only provides operations that can be performed and need to be performed to reduce information overload.
3.For operations that require inputting algebraic formulas, after completing the input, you need to click on the selected algebraic formula, equal sign, and inequality sign to perform the operation. All other operations can be executed after selecting the correct answer.
1.支持深色模式。
2.菜单中仅提供能被执行与需要执行的操作,减少信息过载。
3.对于需要输入代数式的操作,完成输入后需要再点击选择的代数式、等号、不等号,以便执行操作,
其它所有操作选中正确答案后即可执行操作。
8
2025年02月21日
1. System framework: Support to go back to the previous step in the review problem-solving process mode
2. Algebra: Substitute eligible numbers into letters, and observe and find the quantitative relationship.
3. Function: If there is f(x), then x conforms to the definition,
Substitute any algebraic formula that meets the definition into the independent variable of the function to get the function value.
Substitute algebraic expressions into the relevant function independent variables of the inequality
Subset functions inherit the quantitative relationship of parent functions
converted f(u(x)) to f(v(x)), for example, convert f(f(x)) to f(t),convert f(t) to f(f(x))
4. Function monotony
Judge the size of the function value according to the size of the expression
Judge the size of the independent variable according to the value size of the function
Exponential functions, logarithmic functions and other standard functions are classified and discussed according to monotony.
Construct the function value size relationship of any pair of numbers in the definition domain
Get the maximum and minimum values of the closed interval monotonous function
Greater than the maximum value of the function greater than the function
Less than the minimum value of the function less than function
Let the function of two\three sides of the inequality become an isomorphic function.
Determining the monotony of the function includes judging the monotonicity of the function.
5. Judge the oddity of the function
6. The operation properties of logarithms
Construct and judge the symbol of N-1 to judge the symbol of log_a N
Other algebraic formulas that are known to be complied by co-multiplication on both sides of the inequality,
Compare the size of the related quantities of two equations and judge the symbol of the multi-factor product,
Clear some bugs, including problem-solving framework boundaries\exit and re-entry-related bugs
1.系统框架:在复习解题过程模式中支持回退到上一步
2.代数:代入符合条件的数到字母中,观察发现数量关系
3.函数:存在f(x),则x符合定义,
代入任意符合定义的代数式到函数的自变量中求函数值
代入代数式到不等式的相关函数自变量中
子集函数继承父集函数的数量关系
f(u(x))转换为f(v(x)),例如f(f(x))转换位f(t),f(t)转换位f(f(x))
4.函数单调性
依据表达式大小判断函数值大小
依据函数值大小判断自变量大小
指数函数、对数函数等标准函数按单调性分类讨论
构造定义域上的任意一对数的函数值大小关系
闭区间单调函数的最大值与最小值
大于函数大于函数的最大值
小于函数小雨函数的最小值
让不等式两\三边的函数式成为同构函数
判定函数的单调性包括由函数单调判断函数的增减性
5.判断函数的奇偶性
6.对数的运算性质
构造并判断N-1的符号以判断log_a N 的符号
其它 不等式两边同乘已知符合的代数式,
比较两个等式相关数量的大小,判断多因式乘积的符号,
清除一些bug,包括解题框架边界\退出重入相关的bug
2. Algebra: Substitute eligible numbers into letters, and observe and find the quantitative relationship.
3. Function: If there is f(x), then x conforms to the definition,
Substitute any algebraic formula that meets the definition into the independent variable of the function to get the function value.
Substitute algebraic expressions into the relevant function independent variables of the inequality
Subset functions inherit the quantitative relationship of parent functions
converted f(u(x)) to f(v(x)), for example, convert f(f(x)) to f(t),convert f(t) to f(f(x))
4. Function monotony
Judge the size of the function value according to the size of the expression
Judge the size of the independent variable according to the value size of the function
Exponential functions, logarithmic functions and other standard functions are classified and discussed according to monotony.
Construct the function value size relationship of any pair of numbers in the definition domain
Get the maximum and minimum values of the closed interval monotonous function
Greater than the maximum value of the function greater than the function
Less than the minimum value of the function less than function
Let the function of two\three sides of the inequality become an isomorphic function.
Determining the monotony of the function includes judging the monotonicity of the function.
5. Judge the oddity of the function
6. The operation properties of logarithms
Construct and judge the symbol of N-1 to judge the symbol of log_a N
Other algebraic formulas that are known to be complied by co-multiplication on both sides of the inequality,
Compare the size of the related quantities of two equations and judge the symbol of the multi-factor product,
Clear some bugs, including problem-solving framework boundaries\exit and re-entry-related bugs
1.系统框架:在复习解题过程模式中支持回退到上一步
2.代数:代入符合条件的数到字母中,观察发现数量关系
3.函数:存在f(x),则x符合定义,
代入任意符合定义的代数式到函数的自变量中求函数值
代入代数式到不等式的相关函数自变量中
子集函数继承父集函数的数量关系
f(u(x))转换为f(v(x)),例如f(f(x))转换位f(t),f(t)转换位f(f(x))
4.函数单调性
依据表达式大小判断函数值大小
依据函数值大小判断自变量大小
指数函数、对数函数等标准函数按单调性分类讨论
构造定义域上的任意一对数的函数值大小关系
闭区间单调函数的最大值与最小值
大于函数大于函数的最大值
小于函数小雨函数的最小值
让不等式两\三边的函数式成为同构函数
判定函数的单调性包括由函数单调判断函数的增减性
5.判断函数的奇偶性
6.对数的运算性质
构造并判断N-1的符号以判断log_a N 的符号
其它 不等式两边同乘已知符合的代数式,
比较两个等式相关数量的大小,判断多因式乘积的符号,
清除一些bug,包括解题框架边界\退出重入相关的bug
7
2024年02月13日
Simplify the easy computing to reduce steps of implementing
add content:
abstract function f(x)
one Variable Quadratic Equation
compound inequaliy
classification
proof by contradiction/reduction
to make nature inequality m>n(m-n>0)
to make inequality from m>n>0 to sqrt(m)>sqrt(n)
refine relative formula about the addition of rational number
refine solution judge to use compound ineqaulity
Clear other errors and bugs
简化简单计算以大量减少解题步骤
新增内容: 抽象函数f(x)
一元二次方程
复合不等式
分类讨论
反证法
支持不等于不等式,
支持构造自然不等式 m>n(m-n>0)
支持从m>n>构造不等式sqrt(m)>sqrt(n)
改进有数加法相关规则的运用
改进不等式解集判定支持复合不等式
清除其它错误与bugs
add content:
abstract function f(x)
one Variable Quadratic Equation
compound inequaliy
classification
proof by contradiction/reduction
to make nature inequality m>n(m-n>0)
to make inequality from m>n>0 to sqrt(m)>sqrt(n)
refine relative formula about the addition of rational number
refine solution judge to use compound ineqaulity
Clear other errors and bugs
简化简单计算以大量减少解题步骤
新增内容: 抽象函数f(x)
一元二次方程
复合不等式
分类讨论
反证法
支持不等于不等式,
支持构造自然不等式 m>n(m-n>0)
支持从m>n>构造不等式sqrt(m)>sqrt(n)
改进有数加法相关规则的运用
改进不等式解集判定支持复合不等式
清除其它错误与bugs
6.4
2023年06月16日
Support user to know the introduction of math-operation selected by tap the name displayed
Support user to know the introduction of math-operation by tap item of operation list in my page
Add content in how page to introduce how to get introduction info of math-operation
Refine the display of complicated fraction
Refine the display of complicated radial
支持用戶點觸已經選擇的數學操作名稱以查看操作相關的介紹
支持用戶點觸我的頁面的操作清單中數學操作名稱以查看操作相關的介紹
在用法頁增加內容介紹如何查看數學操作的相關介紹
支持用戶点触已经選选择的数学操作名称以查看操作相关的介绍
支持用戶点触我的页面的操作清单中数学操作名称以查看操作相关的介绍
在用法页面增加内容介绍如何查看数学操纵的相关 介绍
Support user to know the introduction of math-operation by tap item of operation list in my page
Add content in how page to introduce how to get introduction info of math-operation
Refine the display of complicated fraction
Refine the display of complicated radial
支持用戶點觸已經選擇的數學操作名稱以查看操作相關的介紹
支持用戶點觸我的頁面的操作清單中數學操作名稱以查看操作相關的介紹
在用法頁增加內容介紹如何查看數學操作的相關介紹
支持用戶点触已经選选择的数学操作名称以查看操作相关的介绍
支持用戶点触我的页面的操作清单中数学操作名称以查看操作相关的介绍
在用法页面增加内容介绍如何查看数学操纵的相关 介绍
6.3
2023年05月22日
Correct the error of V6.2: making demo list to be todo list
更正V6.2的錯誤:將演示習題集設置為待做清單習題集
更正V6.2的错误:将演示习题集设置为待做清单习题集
更正V6.2的錯誤:將演示習題集設置為待做清單習題集
更正V6.2的错误:将演示习题集设置为待做清单习题集
6.2
2023年05月11日
Remove bug of V6.1:
.Bug; a greater than b, n greater than 0, so an greater than bn
.Bug: ab greater than 0, a.less than 0, ab divide a less than 0
.Bug: demoList bug caused by index intersection
清除V6.1的bug
.bug: a greater than b, n greater than 0, so an greater than bn
.bug:ab greater than 0, a.less than 0, ab divide a less than 0
.bug:因索引交叉導致的演示例題bug
.Bug; a greater than b, n greater than 0, so an greater than bn
.Bug: ab greater than 0, a.less than 0, ab divide a less than 0
.Bug: demoList bug caused by index intersection
清除V6.1的bug
.bug: a greater than b, n greater than 0, so an greater than bn
.bug:ab greater than 0, a.less than 0, ab divide a less than 0
.bug:因索引交叉導致的演示例題bug
6.1
2023年05月07日
update how page to show how to use app by new manner
refine the ui for trigger of operation menu
add new operation: |a| greater than |b|,a less than0,a+b less than 0,a greater than 0,a+b greater than 0
refine the compute number product so can compute numerator or denominator or total fraction
enhance replace by opposite: support x=-(-x)
display selected menu item even if unmatched to selected monomials
remove bug for unmatched selection of menu item
remove bug of ab no less than 0,ano less than 0,so b no less than 0
refine a div b no less than 0,a no less than 0,so b greater than 0
refine a div b no less than 0,b greater than 0,so no less than 0
refine ab.no less than 0,a.no less than 0,so b grater than 0
remove bug of no effect to set sigh to input number
更新用法頁簡單說明App的使用方法
改進觸發菜單的UI
新增數學運算:|a|大於|b|,a小於0,a+b小於0,a大於0,a+b大於0
改進計算數積以支持選擇計算分式的分子部分或分母部份或整個分式
增強替換相反數:支持 x=-(-x)
顯示選擇的菜單信息無論是否時匹配的數學操作
移除不匹配菜單項選擇的bug
移除來自 ab不小於0,a不小於0,so b不小於 0 的bug
增強 a div b不小於0,a不小於0,so b大於 0
增強a div b不小於0,b大於0,so a不小於 0
增強 ab 不小於 0,a 不小於 0,so b 不小於 0
移除輸入數時正負號設置失效的bug
refine the ui for trigger of operation menu
add new operation: |a| greater than |b|,a less than0,a+b less than 0,a greater than 0,a+b greater than 0
refine the compute number product so can compute numerator or denominator or total fraction
enhance replace by opposite: support x=-(-x)
display selected menu item even if unmatched to selected monomials
remove bug for unmatched selection of menu item
remove bug of ab no less than 0,ano less than 0,so b no less than 0
refine a div b no less than 0,a no less than 0,so b greater than 0
refine a div b no less than 0,b greater than 0,so no less than 0
refine ab.no less than 0,a.no less than 0,so b grater than 0
remove bug of no effect to set sigh to input number
更新用法頁簡單說明App的使用方法
改進觸發菜單的UI
新增數學運算:|a|大於|b|,a小於0,a+b小於0,a大於0,a+b大於0
改進計算數積以支持選擇計算分式的分子部分或分母部份或整個分式
增強替換相反數:支持 x=-(-x)
顯示選擇的菜單信息無論是否時匹配的數學操作
移除不匹配菜單項選擇的bug
移除來自 ab不小於0,a不小於0,so b不小於 0 的bug
增強 a div b不小於0,a不小於0,so b大於 0
增強a div b不小於0,b大於0,so a不小於 0
增強 ab 不小於 0,a 不小於 0,so b 不小於 0
移除輸入數時正負號設置失效的bug
6.0
2023年02月02日
add content and relative operation of absolute, real and radical
add conclusion type of todo
support traditional Chinese
add many operation: such as a+b>0,a+c>b+c,reverse operation of power, countdown operation of fraction, both multiply at numerator and denominator,remove minus from fraction...
refine power operation and number computing
refine user preference
refine the line of fraction
refine go back operation
refine answer option
1 增加新內容絕對值、實數、根式
2 增加證明題型
3 支持繁體中文
4 增加新操作運算 : such as a+b>0,a+c>b+c冪的各種逆運算,分式的倒數運算,分子分母同乘一個數,移動負號出分數...
5 改進冪運算與數的乘積運算
6 改進用戶偏好
7 改進分數線
8 改進回退操作
9 改進答案選擇清單
add conclusion type of todo
support traditional Chinese
add many operation: such as a+b>0,a+c>b+c,reverse operation of power, countdown operation of fraction, both multiply at numerator and denominator,remove minus from fraction...
refine power operation and number computing
refine user preference
refine the line of fraction
refine go back operation
refine answer option
1 增加新內容絕對值、實數、根式
2 增加證明題型
3 支持繁體中文
4 增加新操作運算 : such as a+b>0,a+c>b+c冪的各種逆運算,分式的倒數運算,分子分母同乘一個數,移動負號出分數...
5 改進冪運算與數的乘積運算
6 改進用戶偏好
7 改進分數線
8 改進回退操作
9 改進答案選擇清單
5.0
2022年05月19日
optimizing for iPad: just tap once to select item of todo list
优化对Ipad的支持:解决在todo中选择习题时需要点击两次的问题
优化对Ipad的支持:解决在todo中选择习题时需要点击两次的问题
4.0
2022年05月17日
multiplication formula, equation,equations,inequality,inequalities,fractionEquation. and get value with relative knowledge.
乘法公式,方程,方程组,不等式,不等式组,分式方程. 及利用相关知识求值.
本版本不支持Ipad
乘法公式,方程,方程组,不等式,不等式组,分式方程. 及利用相关知识求值.
本版本不支持Ipad
3.0
2021年08月19日
1.add integral and fraction
2.use point to express multiplication in relative operation
3.use correct parenthesis () [] {} at relative position of expression
4.erase bugs of v2
1.新增整式与分式
2.在相关运算中用点表示乘法
3.在相关位置正确使用 () [] {}
4.清楚版本V2中的bug
2.use point to express multiplication in relative operation
3.use correct parenthesis () [] {} at relative position of expression
4.erase bugs of v2
1.新增整式与分式
2.在相关运算中用点表示乘法
3.在相关位置正确使用 () [] {}
4.清楚版本V2中的bug
2.0
2021年04月12日
1.support 0 index of exponentiation, such as 2^(4-4),a^(2x-2x)
2.display (x^2)^(2m-3n) correctly
3.report invalid when user input (0),(3) in expression, such as 2(0),4(1)
4.support factoring for 9-4,4-12+9 by completeSquere or SqureDifference
5.support 1^x,1^5,that base nummber equal 1 for exponentiation
6.support sin 1,cos 2....
7. support factoring for 2^2-2*2*3+3^2
8.eliminate several bug which cause exit app when jump between the detail page of how and todo
2.display (x^2)^(2m-3n) correctly
3.report invalid when user input (0),(3) in expression, such as 2(0),4(1)
4.support factoring for 9-4,4-12+9 by completeSquere or SqureDifference
5.support 1^x,1^5,that base nummber equal 1 for exponentiation
6.support sin 1,cos 2....
7. support factoring for 2^2-2*2*3+3^2
8.eliminate several bug which cause exit app when jump between the detail page of how and todo
1.0
2021年03月16日
implementa FAQ
點擊此處瞭解如何在受限國家或地區下載implementa。
以下為implementa的最低配置要求。
iPhone
須使用 iOS 15.0 或以上版本。
iPad
須使用 iPadOS 15.0 或以上版本。
iPod touch
須使用 iOS 15.0 或以上版本。
implementa支持英文

































